In my post '11', I received a comment from
Anjana, who stated an interesting property
of the number 9 :
If you pick a 2-digit number, reverse the
digits, and subtract the smaller number
from the bigger number, you get a multiple
of 9.
I believe that I can explain this, using a
method I worked out :
Step 1 : Start with any number. [Not necessarily a 2-digit number.]
Step 2 : Add up its digits.
Step 3 : Is the result a one-digit number ?
If no, see step 2.
If yes, continue.
Step 4 : This will be its digit root or DR.
Now to start with the property :
The number stated will have a digit root
of 'x'.
Re-arranging the digits does no difference to the
DR, so the second number will also have DR 'x'
Subtracting one number from the other in any order,
will be x - x = 0.
Look at fact 1. So the DR of the difference is also 9.
Since the divisibility of 9 requires a number's Digital Root
to be 9, the difference is divisible by 9.
Thus proved.
Anjana, who stated an interesting property
of the number 9 :
If you pick a 2-digit number, reverse the
digits, and subtract the smaller number
from the bigger number, you get a multiple
of 9.
I believe that I can explain this, using a
method I worked out :
Step 1 : Start with any number. [Not necessarily a 2-digit number.]
Step 2 : Add up its digits.
Step 3 : Is the result a one-digit number ?
If no, see step 2.
If yes, continue.
Step 4 : This will be its digit root or DR.
Now to start with the property :
The number stated will have a digit root
of 'x'.
Re-arranging the digits does no difference to the
DR, so the second number will also have DR 'x'
Subtracting one number from the other in any order,
will be x - x = 0.
Look at fact 1. So the DR of the difference is also 9.
Since the divisibility of 9 requires a number's Digital Root
to be 9, the difference is divisible by 9.
Thus proved.
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